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Pipe and Cistern practice question for Railways, SSC. Review the correct answer and explanation, then continue with related practice below.

Question language / प्रश्न भाषा

Three pipes, A, B and C, are capable of filling a tank in 6, 8 and 12 hours, respectively. When all three pipes are opened together, they operate for 2 hours before pipe C is closed. How much additional time will it take to completely fill the tank after that?

तीन पाइप A, B और C किसी टंकी को क्रमशः 6, 8 और 12 घंटे में भर सकते हैं। तीनों पाइपों को एक साथ खोला जाता है और वे 2 घंटे तक चलते हैं, जिसके बाद पाइप C को बंद कर दिया जाता है। इसके बाद टंकी को पूरी तरह भरने में कितना अतिरिक्त समय लगेगा?

Answer and explanation are free to read — no sign-in required.उत्तर और व्याख्या पढ़ने के लिए साइन-इन आवश्यक नहीं है।

A

6 7 hours 67 घंटे

✓

B

2 6 hours 26 घंटे

C

3 5 hours 35 घंटे

D

9 2 hours 92 घंटे

Correct Answerसही उत्तर

A. 6 7 hours 6A. 7 घंटे

Explanationव्याख्या

Take total capacity as: LCM(6, 8, 12) = 24 units Efficiencies: A = 24 ÷ 6 = 4 units
hour B = 24 ÷ 8 = 3 units
hour C = 24 ÷ 12 = 2 units
hour Combined efficiency: = 4 + 3 + 2 = 9 units
hour Tank filled in 2 hours: = 9 × 2 = 18 units Remaining capacity: = 24 − 18 = 6 units After C is closed, combined efficiency of A and B: = 4 + 3 = 7 units
hour Required additional time: = 6 ÷ 7 = 6
7 hour Hence, the correct answer is 6
7 hour.

अतः सही उत्तर 6
7 घंटा है।

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