Home › Questions › Math › Number System

RailwaysSSCMathNumber SystemMedium

Number System practice question for Railways, SSC. Review the correct answer and explanation, then continue with related practice below.

Question language / प्रश्न भाषा

1024 × 976 = ? 1024 × 976 = ? Explanation

व्याख्या: 1024 = 1000 + 24 976 = 1000 − 24 Therefore, 1024 × 976 = 1000² − 24² = 1000000 − 576 = 999424

Answer and explanation are free to read — no sign-in required.उत्तर और व्याख्या पढ़ने के लिए साइन-इन आवश्यक नहीं है।

A

998904

B

999624

C

999804

D

999424

✓

Correct Answerसही उत्तर

D. 999424

Explanationव्याख्या

Explanation is not available for this older question yet. / इस पुराने प्रश्न की व्याख्या अभी उपलब्ध नहीं है।

Practice More Like This

Vitorr selects questions using the same topic, subject, exam and overlapping concepts—not just database order.

Start 10-Question Related Practice →View All Number System Questions

1008 × 992 = ? 1008 × 992 = ? Explanationव्याख्या: 1008 = 1000+8 992 = 1000−8 Using: (a+b)(a−b)=a²−b² 1008×992 = 1000² − 8² = 1000000 − 64 = 999936Same topic · Same subject · Same exam

1014 × 986 = ? 1014 × 986 = ? Explanationव्याख्या: 1014 = 1000 + 14 986 = 1000 − 14 Using: (a+b)(a−b) = a²−b² 1014 × 986 = 1000² − 14² = 1000000 − 196 = 999804Same topic · Same subject · Same exam

Question 1 Arrange the fractions 5 9, 4 7, 3 5 and 2 3 in ascending order. 9, 4 7, 3 Explanation 5 9 ≈ 55.55% 4 7 ≈ 57.14% 3 5 = 60% 2 3 ≈ 66.67% Therefore:भिन्नों 5 5 और 2 3 को आरोही क्रम में व्यवस्थित कीजिए। व्याख्या Convert the fractions into percentages to compare their values easily. भिन्नों के मानों की आसानी से तुलना करने के लिए उन्हें प्रतिशत में बदलें। अतः:Same topic · Same subject · Same exam

[(946 + 157)² + (946 − 157)²] [(946 × 946) + (157 × 157)] = ? [(946 + 157)² + (946 − 157)²] [(946 × 946) + (157 × 157)] = ? Explanation Therefore, = 2a² + 2b² = 2(a²+b²) The denominator is: a²+b² Therefore, the complete fraction becomes: 2(a²+b²) (a²+b²) Cancel (a²+b²): = 2 Hence, answer = B. 2व्याख्या: Let: a = 946 b = 157 The numerator is: (a+b)² + (a−b)² Expand: (a+b)² = a² + 2ab + b² (a−b)² = a² − 2ab + b² Adding: (a+b)² + (a−b)² = a² + 2ab + b² + a² − 2ab + b² The +2ab and −2ab cancel.Same topic · Same subject · Same exam

{(476 + 424)² − 4 × 476 × 424} = ? {(476 + 424)² − 4 × 476 × 424} = ? Explanationव्याख्या: We know: (a+b)² − 4ab = a² + 2ab + b² − 4ab = a² − 2ab + b² = (a−b)² Therefore, (476+424)² − 4×476×424 = (476−424)² = 52² = 2704Same topic · Same subject · Same exam

(?)² = 351649 (?)² = 351649 Explanationव्याख्या: Check 593²: 593² = (600−7)² = 600² − 2×600×7 + 7² = 360000 − 8400 + 49 = 351649 Therefore, ? = 593 Algebraic IdentitiesSame topic · Same subject · Same exam

Related Quizzes

Continue with quizzes connected to Number System and Math. Sign up is required only when you start a quiz.

Number System Basics Quiz – Types of Numbers, Even-Odd, Prime Numbers & Divisibility RulesOpen quiz →Number System – Divisibility and Remainder Practice QuizOpen quiz →Number System Practice Quiz – 30 QuestionsOpen quiz →UPSC CSAT 2027 Tough Practice Quiz Set 020 – Advanced DI, Mathematics, Probability & Logical ReasoningOpen quiz →

Related Study Material

Number System Complete Notes for SSC & Railway | संख्या पद्धति सम्पूर्ण नोट्सRead study article →NUMBER SYSTEM PRACTICE — 30 QUESTIONSRead study article →Binary Number System and Decimal-Binary Conversion | बाइनरी संख्या एवं रूपांतरणRead study article →