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Question language / प्रश्न भाषा

The difference between the local value and face value of 6 in the numeral 586723 is: Explanation

संख्या 586723 में अंक 6 के स्थानीय मान और अंकित मान के बीच का अंतर कितना है? व्याख्या: In 586723, digit 6 is at the thousands place. Place value of 6 = 6 × 1000 = 6000 Face value of 6 = 6 Difference = 6000 − 6 = 5994 संख्या 586723 में 6 हजार के स्थान पर है। 6 का स्थानीय मान = 6 × 1000 = 6000 6 का अंकित मान = 6 अंतर = 6000 − 6 = 5994

Answer and explanation are free to read — no sign-in required.उत्तर और व्याख्या पढ़ने के लिए साइन-इन आवश्यक नहीं है।

A

723

B

6717

C

5994

✓

D

None of theseइनमें से कोई नहीं

Correct Answerसही उत्तर

C. 5994

Explanationव्याख्या

Explanation is not available for this older question yet. / इस पुराने प्रश्न की व्याख्या अभी उपलब्ध नहीं है।

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If the unit digit in (549 × 56 × 28* × 684) is 8, then what digit will be there in place of *? We only need unit digits: 549 → 9 56 → 6 28* → * 684 → 4 Therefore, 9 × 6 × * × 4 First, 9 × 6 × 4 = 216 So we need the unit digit of: 216 × * Since 216 ends in 6, we need: 6 × * to end in 8. Check options: 6 × 4 = 24 → unit digit 4 6 × 3 = 18 → unit digit 8 6 × 2 = 12 → unit digit 2 6 × 1 = 6 Therefore, = 3 Divisibility and Remainderयदि (549 × 56 × 28 × 684) का इकाई अंक 8 है, तो * के स्थान पर कौन-सा अंक होगा?* Explanation व्याख्या: Here 28* represents a three-digit number whose unit digit is *.Same topic · Same subject · Same exam

Explanation Cycle of 7: 7, 9, 3, 1 764 ÷ 4 = 191 with remainder 0. When remainder is 0, we take the fourth number of the cycle. Therefore, unit digit = 1.The digit in the unit place of (2137)⁷⁶⁴ is: (2137)⁷⁶⁴ का इकाई अंक क्या है? व्याख्या: Only the last digit 7 matters.Same topic · Same subject · Same exam

Explanation Therefore, unit digit = 3. For 3⁵⁸: Cycle = 3, 9, 7, 1 58 ÷ 4 leaves remainder 2. Therefore, unit digit = 9. We need the unit digit of: 7⁹⁵ − 3⁵⁸ At the unit place: 3 − 9 Borrow 10: 13 − 9 = 4 Therefore, unit digit = 4.The unit digit in (7⁹⁵ − 3⁵⁸) is: (7⁹⁵ − 3⁵⁸) का इकाई अंक क्या है? व्याख्या: For 7⁹⁵: Cycle = 7, 9, 3, 1 95 ÷ 4 leaves remainder 3.Same topic · Same subject · Same exam

1008 × 992 = ? 1008 × 992 = ? Explanationव्याख्या: 1008 = 1000+8 992 = 1000−8 Using: (a+b)(a−b)=a²−b² 1008×992 = 1000² − 8² = 1000000 − 64 = 999936Same topic · Same subject · Same exam

12846 × 593 + 12846 × 407 = ? 12846 × 593 + 12846 × 407 = ? Explanationव्याख्या: Take 12846 common: 12846×593 + 12846×407 = 12846(593+407) = 12846 × 1000 = 12846000Same topic · Same subject · Same exam

1024 × 976 = ? 1024 × 976 = ? Explanationव्याख्या: 1024 = 1000 + 24 976 = 1000 − 24 Therefore, 1024 × 976 = 1000² − 24² = 1000000 − 576 = 999424Same topic · Same subject · Same exam

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