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Number System practice question for Railways, SSC. Review the correct answer and explanation, then continue with related practice below.

Question language / प्रश्न भाषा

(11² + 12² + 13² + 14² + …… + 20²) = ? Explanation 6 Sum of squares from 1 to 20: = 20×21×41 6 = 2870 Sum of squares from 1 to 10: = 10×11×21 6 = 385 Required sum: 2870 − 385 = 2485

11² + 12² + 13² + ... + 20² का योग क्या है? व्याख्या: Formula: 1² + 2² + ... + n² = n(n+1)(2n+1)

Answer and explanation are free to read — no sign-in required.उत्तर और व्याख्या पढ़ने के लिए साइन-इन आवश्यक नहीं है।

A

385

B

2485

✓

C

2870

D

3235

Correct Answerसही उत्तर

B. 2485

Explanationव्याख्या

Explanation is not available for this older question yet. / इस पुराने प्रश्न की व्याख्या अभी उपलब्ध नहीं है।

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(2² + 4² + 6² + …… + 20²) = ? Explanation 6 = 385 Therefore, 4 × 385 = 15402² + 4² + 6² + ... + 20² का योग क्या है? व्याख्या: 2² + 4² + 6² + ... + 20² = (2×1)² + (2×2)² + ... + (2×10)² = 4(1² + 2² + ... + 10²) Now, 1² + 2² + ... + 10² = 10×11×21Same topic · Same subject · Same exam

8988 ÷ 8 ÷ 4 = ? 8988 ÷ 8 ÷ 4 = ? Explanationव्याख्या: Division is performed from left to right: 8988 ÷ 8 = 1123.5 Now,Same topic · Same subject · Same exam

1014 × 986 = ? 1014 × 986 = ? Explanationव्याख्या: 1014 = 1000 + 14 986 = 1000 − 14 Using: (a+b)(a−b) = a²−b² 1014 × 986 = 1000² − 14² = 1000000 − 196 = 999804Same topic · Same subject · Same exam

(45 + 46 + 47 + …… + 113 + 114 + 115) = ? Explanation 2 = 71(45+115) 2 = 71 × 160 2 = 71 × 80 = 568045 से 115 तक सभी पूर्णांकों का योग क्या है? व्याख्या: First term, a = 45 Last term, l = 115 Number of terms: n = 115 − 45 + 1 = 71 Sum of arithmetic progression: S = n(a+l)Same topic · Same subject · Same exam

ExplanationThe unit digit in (584 × 428 × 667 × 213) is: (584 × 428 × 667 × 213) का इकाई अंक क्या है? व्याख्या: Only unit digits are required: 4 × 8 × 7 × 3 4 × 8 = 32 → unit digit 2 2 × 7 = 14 → unit digit 4 4 × 3 = 12 → unit digit 2 Therefore, answer = 2.Same topic · Same subject · Same exam

Question 1 Arrange the fractions 5 9, 4 7, 3 5 and 2 3 in ascending order. 9, 4 7, 3 Explanation 5 9 ≈ 55.55% 4 7 ≈ 57.14% 3 5 = 60% 2 3 ≈ 66.67% Therefore:भिन्नों 5 5 और 2 3 को आरोही क्रम में व्यवस्थित कीजिए। व्याख्या Convert the fractions into percentages to compare their values easily. भिन्नों के मानों की आसानी से तुलना करने के लिए उन्हें प्रतिशत में बदलें। अतः:Same topic · Same subject · Same exam

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