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Number System practice question for Railways, SSC. Review the correct answer and explanation, then continue with related practice below.

Question language / प्रश्न भाषा

8988 ÷ 8 ÷ 4 = ? 8988 ÷ 8 ÷ 4 = ? Explanation

व्याख्या: Division is performed from left to right: 8988 ÷ 8 = 1123.5 Now,

Answer and explanation are free to read — no sign-in required.उत्तर और व्याख्या पढ़ने के लिए साइन-इन आवश्यक नहीं है।

A

4494

B

561.75

C

2247

D

280.875 E. None of theseइनमें से कोई नहीं

✓

Correct Answerसही उत्तर

D. 280.875 E. None of theseD. इनमें से कोई नहीं

Explanationव्याख्या

Explanation is not available for this older question yet. / इस पुराने प्रश्न की व्याख्या अभी उपलब्ध नहीं है।

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√? = (88 × 42) ÷ 16 √? = (88 × 42) ÷ 16 Explanationव्याख्या: First calculate: 88 × 42 = 3696 Now, 3696 ÷ 16 = 231 Therefore, √? = 231 Squaring both sides: ? = 231² = (230+1)² = 230² + 460 + 1 = 52900 + 461 = 53361Same topic · Same subject · Same exam

5986 − 2340 = 1496 + ? 5986 − 2340 = 1496 + ? Explanationव्याख्या: 5986 − 2340 = 3646 Now, 1496 + x = 3646 x = 3646 − 1496 = 2150Same topic · Same subject · Same exam

Which of the following fractions is less than 7 8 and greater than 1 3? Explanation 3 < fraction < 7 8 Check A: 1 4 < 1 3, so incorrect. Check B: 23 24 > 7 8, so incorrect. Check C: 11 12 > 7 8, so incorrect. Check D: Compare 17 24 with 1 3: 17 × 3 = 51 24 × 1 = 24 51 > 24 Therefore, 17 24 > 1 3 Now compare 17 24 with 7 8: 17 × 8 = 136 24 × 7 = 168 136 < 168 Therefore, 17 24 < 7 8 Hence, 1 3 < 17 24 < 7 8 Answer = D Basic Arithmeticनिम्नलिखित में से कौन-सी भिन्न 7 8 से कम और 1 3 से अधिक है? व्याख्या: We need: 1Same topic · Same subject · Same exam

(2² + 4² + 6² + …… + 20²) = ? Explanation 6 = 385 Therefore, 4 × 385 = 15402² + 4² + 6² + ... + 20² का योग क्या है? व्याख्या: 2² + 4² + 6² + ... + 20² = (2×1)² + (2×2)² + ... + (2×10)² = 4(1² + 2² + ... + 10²) Now, 1² + 2² + ... + 10² = 10×11×21Same topic · Same subject · Same exam

(11² + 12² + 13² + 14² + …… + 20²) = ? Explanation 6 Sum of squares from 1 to 20: = 20×21×41 6 = 2870 Sum of squares from 1 to 10: = 10×11×21 6 = 385 Required sum: 2870 − 385 = 248511² + 12² + 13² + ... + 20² का योग क्या है? व्याख्या: Formula: 1² + 2² + ... + n² = n(n+1)(2n+1)Same topic · Same subject · Same exam

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