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RailwaysCurrent AffairsCurrent AffairsMedium

Which ordered pair correctly answers both questions about topic 3: (1) Who was the Odisha chief minister at the pavilion inauguration? (2) Which semiconductor material was highlighted for high-power applications?

विषय 3 के दोनों प्रश्नों के क्रमवार सही उत्तर कौन-सी जोड़ी में हैं: (1) मंडप के उद्घाटन में ओडिशा के मुख्यमंत्री कौन थे? (2) उच्च शक्ति वाले अनुप्रयोगों के लिए किस अर्धचालक सामग्री पर जोर दिया गया?
The correct ordered pair is Mohan Charan Majhi followed by Silicon carbide. The first half answers “Who was the Odisha chief minister at the pavi…
RailwaysCurrent AffairsCurrent AffairsMedium

Which ordered pair correctly answers both questions about topic 3: (1) Where was Odisha's SEMICON India pavilion located? (2) Who was the Odisha chief minister at the pavilion inauguration?

विषय 3 के दोनों प्रश्नों के क्रमवार सही उत्तर कौन-सी जोड़ी में हैं: (1) SEMICON India में ओडिशा का मंडप कहाँ था? (2) मंडप के उद्घाटन में ओडिशा के मुख्यमंत्री कौन थे?
The correct ordered pair is Yashobhoomi, New Delhi followed by Mohan Charan Majhi. The first half answers “Where was Odisha's SEMICON India pavil…
RailwaysCurrent AffairsCurrent AffairsMedium

Which ordered pair correctly answers both questions about topic 3: (1) How many potential jobs were associated with Odisha's proposals? (2) Where was Odisha's SEMICON India pavilion located?

विषय 3 के दोनों प्रश्नों के क्रमवार सही उत्तर कौन-सी जोड़ी में हैं: (1) ओडिशा के प्रस्तावों से कितने संभावित रोजगार जुड़े थे? (2) SEMICON India में ओडिशा का मंडप कहाँ था?
The correct ordered pair is Around 6,100 followed by Yashobhoomi, New Delhi. The first half answers “How many potential jobs were associated with…
RailwaysCurrent AffairsCurrent AffairsMedium

Which ordered pair correctly answers both questions about topic 3: (1) What was the approximate value of Odisha's semiconductor investment proposals? (2) How many potential jobs were associated with Odisha's proposals?

विषय 3 के दोनों प्रश्नों के क्रमवार सही उत्तर कौन-सी जोड़ी में हैं: (1) ओडिशा के सेमीकंडक्टर निवेश प्रस्तावों का अनुमानित मूल्य क्या था? (2) ओडिशा के प्रस्तावों से कितने संभावित रोजगार जुड़े थे?
The correct ordered pair is ₹23,600 crore followed by Around 6,100. The first half answers “What was the approximate value of Odisha's semiconduc…
RailwaysCurrent AffairsCurrent AffairsMedium

Which ordered pair correctly answers both questions about topic 3: (1) Which state displayed semiconductor proposals worth about ₹23,600 crore? (2) What was the approximate value of Odisha's semiconductor investment proposals?

विषय 3 के दोनों प्रश्नों के क्रमवार सही उत्तर कौन-सी जोड़ी में हैं: (1) लगभग ₹23,600 करोड़ के सेमीकंडक्टर प्रस्ताव किस राज्य ने प्रदर्शित किए? (2) ओडिशा के सेमीकंडक्टर निवेश प्रस्तावों का अनुमानित मूल्य क्या था?
The correct ordered pair is Odisha followed by ₹23,600 crore. The first half answers “Which state displayed semiconductor proposals worth about ₹…
RailwaysMathNumber SystemMedium

If the unit digit in (549 × 56 × 28* × 684) is 8, then what digit will be there in place of *? यदि (549 × 56 × 28 × 684) का इकाई अंक 8 है, तो * के स्थान पर कौन-सा अंक होगा?* Explanation / व्याख्या: Here 28* represents a three-digit number whose unit digit is *. We only need unit digits: 549 → 9 56 → 6 28* → * 684 → 4 Therefore, 9 × 6 × * × 4 First, 9 × 6 × 4 = 216 So we need the unit digit of: 216 × * Since 216 ends in 6, we need: 6 × * to end in 8. Check options: 6 × 4 = 24 → unit digit 4 6 × 3 = 18 → unit digit 8 6 × 2 = 12 → unit digit 2 6 × 1 = 6 Therefore, = 3 Divisibility and Remainder

RailwaysMathNumber SystemMedium

What is the unit digit in (3254)¹⁷⁹³ × (415)³¹⁷ × (241)⁴⁹¹? (3254)¹⁷⁹³ × (415)³¹⁷ × (241)⁴⁹¹ का इकाई अंक क्या है? Explanation / व्याख्या: (3254)¹⁷⁹³ ends in an even digit because its base ends in 4. (415)³¹⁷ always ends in 5. Any even number multiplied by a number ending in 5 ends in 0. Also, (241)⁴⁹¹ ends in 1, which does not change the unit digit. Therefore, Even number × number ending in 5 × number ending in 1 Unit digit = 0

RailwaysMathNumber SystemMedium

The unit digit in 7¹⁰⁵ is: 7¹⁰⁵ का इकाई अंक क्या है? Explanation / व्याख्या: Unit digits of powers of 7 repeat in a cycle: 7¹ → 7 7² → 9 7³ → 3 7⁴ → 1 Cycle length = 4 105 ÷ 4 gives remainder 1. Therefore, take the first number of the cycle. Unit digit = 7 7 की घातों के इकाई अंक का चक्र: 7, 9, 3, 1 105 को 4 से भाग देने पर शेष 1 आता है। इसलिए इकाई अंक = 7

RailwaysMathNumber SystemMedium

Question 1 Arrange the fractions 5/9, 4/7, 3/5 and 2/3 in ascending order. भिन्नों 5/9, 4/7, 3/5 और 2/3 को आरोही क्रम में व्यवस्थित कीजिए। Explanation / व्याख्या Convert the fractions into percentages to compare their values easily. भिन्नों के मानों की आसानी से तुलना करने के लिए उन्हें प्रतिशत में बदलें। 5/9 ≈ 55.55% 4/7 ≈ 57.14% 3/5 = 60% 2/3 ≈ 66.67% Therefore: अतः:

RailwaysMathNumber SystemMedium

[(946 + 157)² + (946 − 157)²] / [(946 × 946) + (157 × 157)] = ? [(946 + 157)² + (946 − 157)²] / [(946 × 946) + (157 × 157)] = ? Explanation / व्याख्या: Let: a = 946 b = 157 The numerator is: (a+b)² + (a−b)² Expand: (a+b)² = a² + 2ab + b² (a−b)² = a² − 2ab + b² Adding: (a+b)² + (a−b)² = a² + 2ab + b² + a² − 2ab + b² The +2ab and −2ab cancel. Therefore, = 2a² + 2b² = 2(a²+b²) The denominator is: a²+b² Therefore, the complete fraction becomes: 2(a²+b²)/(a²+b²) Cancel (a²+b²): = 2 Hence, answer = B. 2