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If 1 occurs 2y times, 2 occurs y times and 4 occurs 4y times, then find the mean for the following observations.

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Finding the Mean of Given Observations

English

Question

If 1 occurs 2y times, 2 occurs y times, and 4 occurs 4y times, find the mean of the observations.

Concept

When different observations occur with different frequencies, we use:

Mean = Σfx / Σf

where:

  • x = observation/value

  • f = frequency

  • fx = value × frequency

  • Σfx = sum of all products

  • Σf = total frequency

Solution

Observation (x)Frequency (f)fx
12y2y
2y2y
44y16y
Total7y20y

Therefore,

Total sum of observations = 20y

and

Total number of observations = 7y

Now,

Mean = Σfx / Σf

= 20y / 7y

Cancelling y:

Mean = 20/7

or approximately:

2.857

🎯 Final Answer

20/7


हिंदी

प्रश्न

यदि 1 की आवृत्ति 2y, 2 की आवृत्ति y तथा 4 की आवृत्ति 4y है, तो इन प्रेक्षणों का माध्य ज्ञात कीजिए।

अवधारणा

जब अलग-अलग मान अलग-अलग बार आते हैं, तो माध्य ज्ञात करने का सूत्र है:

माध्य = Σfx / Σf

जहाँ:

  • x = प्रेक्षण या मान

  • f = आवृत्ति

  • fx = मान × आवृत्ति

  • Σfx = सभी गुणनफलों का योग

  • Σf = कुल आवृत्ति

हल

प्रेक्षण (x)आवृत्ति (f)fx
12y2y
2y2y
44y16y
कुल7y20y

अतः,

सभी प्रेक्षणों का कुल योग = 20y

और

प्रेक्षणों की कुल संख्या = 7y

अब,

माध्य = Σfx / Σf

= 20y / 7y

यहाँ y कट जाएगा।

अतः,

माध्य = 20/7

दशमलव रूप में:

≈ 2.857

🎯 अंतिम उत्तर

20/7


Quick Revision / त्वरित पुनरावृत्ति

Formula

Mean = Σfx / Σf

Step 1

Multiply each observation by its frequency.

प्रत्येक प्रेक्षण को उसकी आवृत्ति से गुणा करें।

Step 2

Add all the products.

सभी गुणनफलों को जोड़ें।

Step 3

Add all the frequencies.

सभी आवृत्तियों को जोड़ें।

Step 4

Divide the total of fx by the total frequency.

Σfx को कुल आवृत्ति Σf से भाग दें।

Exam Shortcut

Here the frequencies are in the ratio:

2y : y : 4y = 2 : 1 : 4

So y is a common factor and does not affect the mean.

Therefore, we can directly calculate:

Mean = (1×2 + 2×1 + 4×4)/(2+1+4)

= (2 + 2 + 16)/7

= 20/7

Important Point

The mean is not:

(1 + 2 + 4)/3 = 7/3

because the three values do not occur equally often.

Their frequencies must be taken into account.




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